400=-16t^2+128t+144

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Solution for 400=-16t^2+128t+144 equation:



400=-16t^2+128t+144
We move all terms to the left:
400-(-16t^2+128t+144)=0
We get rid of parentheses
16t^2-128t-144+400=0
We add all the numbers together, and all the variables
16t^2-128t+256=0
a = 16; b = -128; c = +256;
Δ = b2-4ac
Δ = -1282-4·16·256
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{128}{32}=4$

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